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Grade 10Magical Mathematics[Interesting Approach]

Find the number of positive integers <1000 that can be expressed as 2k2m, where k and m are non-negative integers.

How to solve this?


Profile image of Adhiraj  Mandal
13 Years agoGrade 10
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6 Answers

Profile image of tejas naresh patel
13 Years ago

1

Profile image of Akash Kumar Dutta
ApprovedApproved Tutor Answer13 Years ago

2k-2m=2(k-m)=2a...(a>0)=even number=2,4,6......998
total nos. are=n-1=996/2
                     =>n=499 (ANS)

Profile image of mohit yadav
13 Years ago

 the no. of positive int. <1000 are 499.

Profile image of shiddhant bhattacharya
13 Years ago

is the ans 500*500?? its given tat 2k-2m<1000 , so k-m<500

now as both k&m are non negative integers, the possibilities of both k & m are from 0 to 499.

so for value of k v have500 possibilities of m

so for 500 values of k v hav 500*500 possibilities of m

 

hence i think the ans is (500)^2

Profile image of Adhiraj  Mandal
13 Years ago

dear Siddhant,500*500=2500>1000

Profile image of Shivam Dimri
13 Years ago

acording to me the asnwer should be 499