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it is a result in most of the iit books that |z| 2 = |z 2 | sustituting z=i LHS= |i| 2 = i 2 = -1 RHS= |i 2 | = |-1| = 1 why is this problem occuring though the result is used in many books ?

it is a result in most of the iit books that  |z|2 = |z2|


sustituting z=i


LHS= |i|2 = i2 = -1


RHS= |i2| = |-1|  = 1


why is this problem occuring though the result is used in many books ?

Grade:11

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

DEar Raghunath

you have written

LHS= |i|2 = i2 = -1

this is a mod you can't open mod in this way

correct way is

      |i|2    = |0+i|2

                 =√(02+12)

                 =1

but you open mod as a simple bracket which is wrong.



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