We have am= a+(m-1)d=n........(1) and an= a+(n-1)d=m........(2)Solving (1) & (2), we get (m-n)d= n-m, or d= -1,And a=n+m-1Therefore ap = a+(p-1)d =n+m-1+(p-1) (-1)= n+m-pHence, the pth term is n+m-p.
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