# If the distances from origin of the centres of 3 circles x2+y2+2alphaix= a2 (i=1,2,3) are in G.P. , then length of the tangents drawn to them frm any point on the circles x2+y2 = a2 are in : (a) A.P (b) G.P (c) H.P (d) None of these ans. is (b) ...plzz explain..

Har Simrat Singh
42 Points
11 years ago

centres of the 3 circles are (-alphai,0) (i= 1,2,3)

Distances of thes from origin are alpha1, alpha2, alpha 3

now (alpha2)^2= (alpha1)(alpha3)

Also general point on  x2+y2=a2 is (a costheta, a sintheta) length of tangent from this point on the given circle is

sqrt( (a cos theta)2+(a sintheta)2 +2alphai(a costheta) -a2)) = sqrt ( 2alphai(a costheta))

now as alpha 1, alpha 2, alpha 3 are in GP

then sqrt alpha 1, sqrt alpha 2, sqrt alpha 3 are in gp

then sqrt 2acos theta alpha 1 , 2acos theta alpha 2 and sqrt 2acos theta alpha 3 are also in GP

Arun Kumar IIT Delhi
$\alpha_{1},\alpha_{2},\alpha_{3}...GP \\Tangent^2=(asin(\theta)+\alpha_{i})^2+acos(\theta)^2-(a^2-\alpha_{i}^2) \\=2a\alpha_{i}sin(\theta)+2\alpha_{i}^2$