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f(x+y+z) =f(x).f(y).f(z) for all x , y , z and f(2)=4 , f(0) =3 then f(2) =
ans is 12
plzz explain..
i think the question is wrong as keep x=0 and y=0 then f(z)=f(0).f(0).f(z) then f(0) should be equal to 1 or -1 but it was given f(0)=3
ques. is crect , actually it is f ''(0) =3
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