Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

1) IF A SERIES OF TERMS IN ARTHMETIC PROGRESSION BE COLLECTED INTO GROUPS OF N TERMS AND THE TERMS IN EACH GROUP BE ADDED TOGETHER, THEN THE RESULT FORMS AN ARTHEMETIC PROGRESSION, THEN THE RATIO OF THE COMMON DIFFERENCE OF THAT ARTHEMETIC PROGRESSION TO THE ORGINAL COMMON DIFFERENCE. (A)n 2 :1 (B)n 2 +1:1 (C)n 2 -1:1 (D) n-1:n+1

1) IF A SERIES OF TERMS IN ARTHMETIC PROGRESSION BE COLLECTED INTO GROUPS OF N TERMS AND THE TERMS IN EACH GROUP BE ADDED TOGETHER, THEN THE RESULT FORMS AN ARTHEMETIC PROGRESSION, THEN THE RATIO OF THE COMMON DIFFERENCE OF THAT ARTHEMETIC PROGRESSION TO THE ORGINAL COMMON DIFFERENCE.


(A)n2 :1  (B)n2 +1:1  (C)n2 -1:1  (D) n-1:n+1

Grade:12

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
12 years ago

Dear dilip

let first term is a and common difference is d

so first term of new series   = n/2[2a +(n-1)d]

and second term of new series =2n/2[2a +(2n-1)d] -n/2[2a +(n-1)d]

so common difference of new series  d' =2n/2[2a +(2n-1)d] -n/2[2a +(n-1)d] -n/2[2a +(n-1)d]

                                                         =2n/2[2a +(2n-1)d -n[2a +(n-1)d]

  or d'/d =n2/1

Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free