shivang belwariar
Last Activity: 12 Years ago
2^2/3 is the answer
firstly differentiate and equate the equation to zero
x,y and z are in AP
so, 2y = x+z
Now by
AM>= GM
so,(x+y+z)/3 >= cube root (x*y*z)
So,3y/3>=cube root(x*y*z)
=>y>=4^1/3
=>y>= 2^2/3
So,minimum value of y = 2^2/3
approve it plz