Like tan 3# = 3tan# - tan 3 #/1 -3tan 2# then how to find tan 4#, tan 5#, tan 6#........... so we donot hve to memorize it till last :consider # as thitha angle’

Question

Like tan 3# = 3tan# - tan 3 #/1 -3tan 2# then how to find tan 4#, tan 5#, tan 6#........... so we donot hve to memorize it till last :consider # as thitha angle&rsquo;

eaishwary bajpai · Answer

solve tan4# as taking 4# = 2(2#) tan(5#) = tan (2# + 3#) tan(6#) = tan2(3#)

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Like tan 3# = 3tan# - tan 3 #/1 -3tan 2# then how to find tan 4#, tan 5#, tan 6#........... so we donot hve to memorize it till last :consider # as thitha angle’

Like tan 3# = 3tan# - tan³#/1 -3tan^2#

^{then how to find tan 4#, tan 5#, tan 6#...........
so}we donot hve to memorize it till last

:consider # as thitha angle’

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Like tan 3# = 3tan# - tan 3 #/1 -3tan 2# then how to find tan 4#, tan 5#, tan 6#........... so we donot hve to memorize it till last :consider # as thitha angle’

Like tan 3# = 3tan# - tan3#/1 -3tan2# then how to find tan 4#, tan 5#, tan 6#........... so we donot hve to memorize it till last :consider # as thitha angle’

1 Answers

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Like tan 3# = 3tan# - tan³#/1 -3tan^2#

^{then how to find tan 4#, tan 5#, tan 6#...........
so}we donot hve to memorize it till last

:consider # as thitha angle’