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Like tan 3# = 3tan# - tan3#/1 -3tan2# then how to find tan 4#, tan 5#, tan 6#........... so we donot hve to memorize it till last :consider # as thitha angle’
Like tan 3# = 3tan# - tan3#/1 -3tan2#
then how to find tan 4#, tan 5#, tan 6#........... so we donot hve to memorize it till last
:consider # as thitha angle’
solve tan4# as taking
4# = 2(2#)
tan(5#) = tan (2# + 3#)
tan(6#) = tan2(3#)
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