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If the circle x2+y2+4x+22y+c=0 bisects the circumference of the circle x2+y2-2x+8y-d=0 , then c+d equals to?
eqn of line through intersection of 2 circles : s1-s2=0 ; where s1,s2 are eqns of the 2 circles.
we get line as 6x+14y+c+d=0. this line is a diameter of the circle whose circumference is bisected.
Therefore centre of that circle lies on that line => (1,-4) lies on that line.
=> c+d=50 //
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