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when 6^83+8^83 is divided by 49 , tell the remainder left where ^ denotes raised to?
PLS EXPLAIN (Acco. to me its 0)......
we can write this question as
(7-1)89 + (7+1)89.
open this binomially
= ( 89C0789 - 89C1788 + 89C2787 +... - 89C8772 + 89C8871 - 89C8970) + (89C0789 + 89C1788 + 89C2787 + ...- 89C8772 + 89C8871 - 89C8970)
=2*( 89C0789 + 89C2787 + 89C4785 +...+ 89C8673+ 89C8871)
89C0789+89C2787+89C4785+...+89C8673 will all be divisible by 49 because they consist of 72 as one of their factor but not
so dividing this 2(89C8871) by 49
we get 2(89C8871)%49 = 21 ---Remainder
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