3 identical dices are rolled together . what is the probability that same no appear on the dice . correect ans is 1/6. how is it plz tell me. and the total cases will not be 216 as replied before......? answer this ques plzas soon as psble

divide rolling of the three dice as three independent events,the appearence of a given no on the dice has a probability of 1/6,the other dice have their entry fixed that is in this condition they must show up the no. appearing on dice 1 hence their probability is 1 and 1.since these are independent total probability is 1/6 * 1 * 1 =1/6

total no of possible outcomes = 6 on one dice *6 of second dice * 6 of third dice

=6*6*6

=216

posiblility all have same no

111

222

333

444

555

666

out of 216 outcomes the probability of having all the same no is 6 (not 36)

6/216

=1/36