A man alternately tosses a coin and throws a die beginning with the coin. Find the probability he gets a head in the coin before he gets a 5 or 6 in the die. ANSWER-3/4

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Sher Mohammad · Answer

.5+.5*4/6*.5+5*4/6*.5 *4/6*.5............. .5(1+2/6+ (2/6)^2..........)=.5* 1/(1-2/6)=3/4 sher mohammad b.tech, iit delhi

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A man alternately tosses a coin and throws a die beginning with the coin. Find the probability he gets a head in the coin before he gets a 5 or 6 in the die. ANSWER-3/4

A man alternately tosses a coin and throws a die beginning with the coin. Find the probability he gets a head in the coin before he gets a 5 or 6 in the die. ANSWER-3/4

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A man alternately tosses a coin and throws a die beginning with the coin. Find the probability he gets a head in the coin before he gets a 5 or 6 in the die. ANSWER-3/4

A man alternately tosses a coin and throws a die beginning with the coin. Find the probability he gets a head in the coin before he gets a 5 or 6 in the die. ANSWER-3/4

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Magical Mathematics[Interesting Approach]

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