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The probbltys of 3 mutually exclusive events are respectively (1-2p)/2,(1-p)/2,(1+3p)/3
Then:
a)1/3< p<1/2
b)0<p<1/2
c)1/3<p<2/3
d)0<p<2/3
Plz explain...
1-2p≥0,p≤1/2, similarly p≤1 and p≥-(1/3), 1-2p≤2,p>= -(1/2), similarly,p>= -1 and p≤2/3
so p≤(1/2) and p≥-(1/3), thus -(1/3)≤p≤(1/2)
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