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The probbltys of 3 mutually exclusive events are respectively (1-2p)/2,(1-p)/2,(1+3p)/3 Then: a)1/3 p 1/2 b)0 p 1/2 c)1/3 p 2/3 d)0 p 2/3 Plz explain...

The probbltys of 3 mutually exclusive events are respectively (1-2p)/2,(1-p)/2,(1+3p)/3


Then:


a)1/3< p<1/2


b)0<p<1/2


c)1/3<p<2/3


d)0<p<2/3


  Plz explain...

Grade:12

1 Answers

Chetan Mandayam Nayakar
312 Points
11 years ago

1-2p≥0,p≤1/2, similarly p≤1 and p≥-(1/3),  1-2p≤2,p>= -(1/2), similarly,p>= -1 and p≤2/3

so p≤(1/2) and p≥-(1/3), thus -(1/3)≤p≤(1/2)

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