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sum of 3 prime nos is 100........one differs another by 36........find the largest no.......EXPLAIN!!!
Let the nos be a,b,c
a+b+c=100....[1]
a-b=36....[2]
From [1]and[2]
2b+c=64
As 2b and 64 are even c must be even.
Now the only even prime is 2. Hence c is 2.
2b+2=64=>b=31
a=36+b=67
the largest no. is 67
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