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sum of 3 prime nos is 100........one of them differ by 36........find the largest no.......EXPLAIN!!!!!
Let the nos be a,b,c a+b+c=100....[1] a-b=36....[2] From [1]and[2] 2b+c=64 As 2b and 64 are even c must be even. Now the only even prime is 2. Hence c is 2. 2b+2=64=>b=31 a=36+b=67 the largest no. is 67
Let the nos be a,b,c
a+b+c=100....[1]
a-b=36....[2]
From [1]and[2]
2b+c=64
As 2b and 64 are even c must be even.
Now the only even prime is 2. Hence c is 2.
2b+2=64=>b=31
a=36+b=67
the largest no. is 67
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