Aman Bansal
Last Activity: 13 Years ago
dear akshay,
Let h1 and r1 be the height and radius of the base of the smaller cone and h2 ( = 60 cm ) and r2be the height and radius of the bigger cone. here h1 / h2 = r1 / r2. ( Similar triangles ) ----- ( 1 )
Now according to the question
( (1 /3 ) pai* r1 2 h1 ) / (( 1/3) pai * r2 2 h2 ) =1 / 64
r1 2*h1 / r2 2*h2 = 1 / 64 h1 3 / h2 3 = 1 / 64 ( by applying relation 1 )
h1 / h2 = 1 / 4 or h1 / 60 = 1 / 4 ( since h2 = 60 )
or h1 = 15 cm. There the height from the base at which the section is made = 60 - 15 = 45 cm.Let h1 and r1 be the height and radius of the base of the smaller cone and h2 ( = 60 cm ) and r2be the height and radius of the bigger cone. here h1 / h2 = r1 / r2. ( Similar triangles ) ----- ( 1 )
Now according to the question
( (1 /3 ) pai* r1 2 h1 ) / (( 1/3) pai * r2 2 h2 ) =1 / 64
r1 2*h1 / r2 2*h2 = 1 / 64 h1 3 / h2 3 = 1 / 64 ( by applying relation 1 )
h1 / h2 = 1 / 4 or h1 / 60 = 1 / 4 ( since h2 = 60 )
or h1 = 15 cm. There the height from the base at which the section is made = 60 - 15 = 45 cm.
BEST OF LUCK..!!!!
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AMAN BANSAL