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x to the power of 2006, divided by x2-1 leaves the remainder????????? Pls explain!!!!!!
FIRST WRITE X TO POWER 2006 AS X-1+1 TO POWER 2006...DEN EXPAND IT USING BINOMIAL NEXPANSION...DEN DIVIDE IT BY X2-1 ..U WL GET D ANS...
Dear student, The remainder would be x raise to the power 2004
Dear student,
The remainder would be x raise to the power 2004
this is an example how to divide a polynomial function... Example Divide x4 + 3x2 - 5 x2 + 4x Solution We first write in long division form Next decide what we need to multiply x2 by to get x4. Since (x2)(x2) = x4 we can write Next, we multiply x2 + 7x and x2. Now subtract to get and bring down the 3x2 to get We repeat this process until the degree of the remainder is less than the degree of the denominator. when x2006 is divided by x2-1 then remainder is x2004 by using this method ...
this is an example how to divide a polynomial function...
Example
Divide
x4 + 3x2 - 5 x2 + 4x
Solution
We first write in long division form
Next decide what we need to multiply x2 by to get x4. Since
(x2)(x2) = x4
we can write
Next, we multiply x2 + 7x and x2.
Now subtract to get and bring down the 3x2 to get
We repeat this process until the degree of the remainder is less than the degree of the denominator.
when x2006 is divided by x2-1 then remainder is x2004 by using this method ...
hi i think the remainder is 1..............
hi
i think the remainder is 1..............
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