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ABC IS A TRIANGLE AND AD AND BE ARE ITS MEDIANS AND DF II BE.SHOW THAT BC =4CF.
wen u draw the diagram u can understand properly. using the similar triangles principle in the triangle CEB, using the condition that BE II DF we get EC=2CF , DC=2CF then since BE, AD ARE the medians to AC,BC AC=2CE , BC=2CD sustituting this in the above condition we get AC=4CF, Ans.BC=4CF
wen u draw the diagram u can understand properly.
using the similar triangles principle in the triangle CEB, using the condition that BE II DF
we get EC=2CF , DC=2CF
then since BE, AD ARE the medians to AC,BC
AC=2CE , BC=2CD
sustituting this in the above condition we get
AC=4CF, Ans.BC=4CF
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