Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

what is the next 3 terms of .......tanx=x + 'x'qube by3 +2.'x'raised to a power5 by15 OR X+X^3/3+2X^5/15+ NEXT 3 TERS WHAT??????

what is the next 3 terms of .......tanx=x + 'x'qube by3 +2.'x'raised to a power5 by15 OR X+X^3/3+2X^5/15+ NEXT 3 TERS WHAT??????

Grade:

1 Answers

Pramod J AskiitiansExpert-IIT-B
36 Points
10 years ago

Dear student,

\tan x = \sum^{\infin}_{n=1} \frac{B_{2n} (-4)^n (1-4^n)}{(2n)!} x^{2n-1} = x + \frac{x^3}{3} + \frac{2 x^5}{15} + \cdots\text{ for }|x| < \frac{\pi}{2}\!

 

where B is a bernoulli series

 B_m(n)=\sum_{k=0}^m\sum_{v=0}^k(-1)^v\binom kv\frac{\left( n+v\right) ^m}{k+1} ,

 

fourth term of the series is 17x^7/315 other two 2 can be solved by the above formula

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free