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```        If "2+ squareroot (3)" is a root of the equation x^2 + px + q = 0 , then write the values of p and q .
8 years ago

```							let A,B are the roots of this equation then
A+B = -p      ,    AB = q
if one root is 2+31/2 then other can be 2-31/2 or 31/2-2
case 1) (A,B) = (2+roo3 , 2-root3)                                 case2) (A,B) = (root3-2) , (root3+2)
A+B = 4 = -P                                                                       A+B = 2root3 = -p
AB = 4-3 = 1 = q                                                                      AB = -1   = q
now we have two odered pairs for (p,q)
p,q ={ (-4,1) , (-2root3,-1) }
```
8 years ago
```							Dear student,
Sum of the roots=-p
Product =q
Now one of the roots is given 2+root3
You can easily finc the value of p and q

All the best.
Win exciting gifts by                                                                                                                                                                                           answering         the                            questions          on                                     Discussion                                  Forum.        So                        help                                          discuss                           any                                         query            on                                      askiitians                     forum        and                               become       an                          Elite                                         Expert                     League                                                    askiitian.

Sagar Singh
B.Tech, IIT Delhi

```
8 years ago
```							if p n q are real no.s then if 2+sqrt3 is root then 2-sqrt3 has to b d root as well.
thr4 p=-4    q=1
```
8 years ago
```							Thanks a lot guys ! :)
```
8 years ago
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