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there is a triangle whose angles are 45, 75, 60. if the side opp. to 75 angle is 9cm then find the value of side opp. to 60 degree????? pls explain!!
here we can use sine rule , according to this rule => ratio of side & sine of oppsite angle is constant.. a/sinA = b/sinB = c/sinC = K side opposite to 75o is 9 so ratio = 9/sin75o let opposite side to 60o is x then ratio = x/sin60o ratio is constant so x/sin60 = 9/sin75 x = (9sin60/sin75) sin75 = (root3+1)/2(root2) , sin60 = root3/2 so , x = 9root6/(root3+1) ans
here we can use sine rule , according to this rule
=> ratio of side & sine of oppsite angle is constant..
a/sinA = b/sinB = c/sinC = K
side opposite to 75o is 9 so ratio = 9/sin75o
let opposite side to 60o is x then ratio = x/sin60o
ratio is constant so x/sin60 = 9/sin75
x = (9sin60/sin75)
sin75 = (root3+1)/2(root2) , sin60 = root3/2
so , x = 9root6/(root3+1) ans
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