In a triangle if the lenght of the sides are a,b,c.then the given condition is a2+b2+c2=ab+bc+ca.then the triangle formed is a]right angled b]obtuse angled c]acute angled........[I want to know about the angle of the triangle ...so please help me to solve this problem]

a²+b²+c² = ab+bc+ac               (given)

cosA = b²+c²-a²/2bc

2bccosA = b²+c²-a²           ...........1

2accosB = a²+c²-b²             ..........2

2abcosC = a²+b²-c²            .........3

adding 1,2,3

2(abcosC+bccosA+accosB) = a²+b²+c²       ........4

a²+b²+c² = ab+bc+ac              (given)

so , 2(abcosC+bccosA+accosB) = ab+bc+ac

      2ab(cosC-1/2) + 2bc(cosA-1/2) + 2ac(cosB-1/2) = 0

from this eq , cosC = cosA = cosB = 1/2

A=B=C = Pi/3

so the triangle is equilateral , acute angled triangle...

approve if u like my ans

though this isnt the exact solution but if you are looking for answer directly

the above condition satisifies when a=b=c,so it can be equilateral corresponds to the answer acute angled