The short and long hands of a clock are 4 cm and 6 cm respectively. Find the sum of the distances travelled by their tips in two days.

Question

Raju Garg · Answer

area of short hand = 22/7*4 =88/7

total area in two days = 88/7*4=362/7

area of long hand = 22/7*6=132/7

total area in two days=132/7*48=6336/7

total area covered in two days = 6336/7+362/7=6698/7 = 956.85

Swag buddy · Answer

Round travel by show than in 2 days is equal to 4 and round travelled by long hand in 2 days is equal to 48 there for distance travelled by tips of the hands in 2 days will be there circumference is that4×2π4+48×2π6=1911.71

Swag buddy · Answer

Round travel by short hand*( it was miss printed in the previous answer) in 2 days is equal to 4 and round travelled by long hand in 2 days is equal to 48 there for distance travelled by tips of the hands in 2 days will be there circumference is that4×2π4+48×2π6=1911.71

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The short and long hands of a clock are 4 cm and 6 cm respectively. Find the sum of the distances travelled by their tips in two days.

The short and long hands of a clock are 4 cm and 6 cm respectively. Find the sum of the distances travelled by their tips in two days.

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