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The diameters of two given circles are as 3 : 4, and the sum of the areas of the circles is equal to the area of a circle whose diameter measures 30 c. Find the diameters of the given circles.
area of first circle = 22/7*(3x)2=22/7*9x2=198x2/7 area of second circle=22/7(4x)2=22/7*16x2=352x2/7 total area of circles = 198x2/7+352x2/7 = 550x2/7 area of third circle = 22/7*(30)2=22/7*900=19800/7 total area of circles = area of third circle 550x2/7 = 19800/7 550x2=19800 x2=19800/550=36 x = 6 diameter of circles = 6*3*,6*4* =18,24
area of first circle = 22/7*(3x)2=22/7*9x2=198x2/7
area of second circle=22/7(4x)2=22/7*16x2=352x2/7
total area of circles = 198x2/7+352x2/7 = 550x2/7
area of third circle = 22/7*(30)2=22/7*900=19800/7
total area of circles = area of third circle
550x2/7 = 19800/7
550x2=19800
x2=19800/550=36
x = 6
diameter of circles = 6*3*,6*4*
=18,24
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