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The hypotenuse of a right triangle is 6 more than twice the shortest side. If the third side is 2 m less than the hypotenuse, find the sides of the triangle.
Let the shortest side be x Then , hypotenuse = (x+6) and the third side =(x+6)-2 = (x+4) By applying pythagoras theorm, (x+6)2 = (x+4)2 + x2 x2 - 4x - 20=0 Hence, we can find the value of x and hence all the three sides. Please Approve!
Let the shortest side be x
Then , hypotenuse = (x+6)
and the third side =(x+6)-2 = (x+4)
By applying pythagoras theorm,
(x+6)2 = (x+4)2 + x2
x2 - 4x - 20=0
Hence, we can find the value of x and hence all the three sides.
Please Approve!
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