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if f(y,0)=y+1, f(o,x)=x; f(y,x)=f(f(y,0),f(2*y-1)) then find f(1,1),f(2,3),f(3,0)
Dear sairam ..!
Please check out the expression...i guess something is missing in the last function .. f(f(y,0),f(2y-1,.....))
There must be a variable at the dotted spot
Regards
Yagya
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