Join now for JEE/NEET and also prepare for Boards Class 10 Boards Cancelled! What to do next ? Ask our Experts in a Free Counseling Session Now ! Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91 7353221155
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
If sec A + tan A = p, then the value of sin A is?
secA+tanA =p
1+sinA/cosA = p
1+sinA = pcosA
squaring both sides
1+ sin2A + 2sinA = p2cos2A (cos2A = 1-sin2A)
sin2A(1+p2) + 2sinA + 1-p2 = 0
this is a quadratic eq and roots of eq are
sinA = [-b+(-)(b2-4ac)1/2]/2a
=-1 , (p2-1/p2+1)
sinA = -1 cannot be the root of the eq because it doesnot satisfies the given eqpression so
the only root is
sinA = p2-1/p2+1
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !