Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
If sec A + tan A = p, then the value of sin A is?
secA+tanA =p 1+sinA/cosA = p 1+sinA = pcosA squaring both sides 1+ sin2A + 2sinA = p2cos2A (cos2A = 1-sin2A) sin2A(1+p2) + 2sinA + 1-p2 = 0 this is a quadratic eq and roots of eq are sinA = [-b+(-)(b2-4ac)1/2]/2a =-1 , (p2-1/p2+1) sinA = -1 cannot be the root of the eq because it doesnot satisfies the given eqpression so the only root is sinA = p2-1/p2+1
secA+tanA =p
1+sinA/cosA = p
1+sinA = pcosA
squaring both sides
1+ sin2A + 2sinA = p2cos2A (cos2A = 1-sin2A)
sin2A(1+p2) + 2sinA + 1-p2 = 0
this is a quadratic eq and roots of eq are
sinA = [-b+(-)(b2-4ac)1/2]/2a
=-1 , (p2-1/p2+1)
sinA = -1 cannot be the root of the eq because it doesnot satisfies the given eqpression so
the only root is
sinA = p2-1/p2+1
Find solution of question on doubt solving app Instasolv
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -