Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
A cone is cut half way through its axis and parallel to the base, the volumes of two portions are in the ratio?
let vertex of cone is A ...
after drawing the axis about which cone is to cut , then we will see that there will be two similar triangles ...
radius of base of upper half is r1 & radius of base is R , height of original cone is 2H then
by using similarity of triangles , r1/H = R/2H
r1 = R/2
area of upper half = 1/3 (pi) (r1)2H = 1/3(pi)(R2H/4)
area of lower half = area of cone - area of upper half
=1/3(pi)(R22H) - 1/3(pi)(R2H/4)
=1/3pi(7R2H/4)
ratio of two parts = upper half/lower half = 1/7
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !