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1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)=1/6 1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)=1/6
hi mohit, dis problem is quite simple as u only hav to write each term in the form of difference as for d st term,u write (x-1)-(x-2) in d numerator n simply do it for all d 3 terms n u will get finally 1/(x-4) - 1/(x-1) = 1/6 now it is a simple quadratic n ur ans will be x=7 , x=-2
hi mohit,
dis problem is quite simple as u only hav to write each term in the form of difference as for d st term,u write (x-1)-(x-2) in d numerator n simply do it for all d 3 terms n u will get finally 1/(x-4) - 1/(x-1) = 1/6
now it is a simple quadratic n ur ans will be x=7 , x=-2
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