1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)=1/6

Question

Pratham Ashish · Answer

hi mohit,

dis problem is quite simple as u only hav to write each term in the form of difference as for d st term,u write (x-1)-(x-2) in d numerator n simply do it for all d 3 terms n u will get finally 1/(x-4) - 1/(x-1) = 1/6

now it is a simple quadratic n ur ans will be x=7 , x=-2

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1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)=1/6

1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)=1/6

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