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If the integers m and n are chosen at random between 1 and 100, then the probability that a number of the form 7m+7n is divisible by 5 is?
Answer is given as 1/5
Plz explain
The answer is 1/5. The total possibilities are....(7,3), (7,9), (7,1), (3,9),(3,1),(9,1),(7,7),(9,9),(3,3),(1,1).......
Among these oly (7,3) and (9,1) satisfy the condition.....so we can take the probability as 2/10 ie 1/5
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