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Hiii pranav its very easy dude !
First find the minimum value of the equation f(x) = y^2 - 4y + 11
Minimum value = -D/4a where D is discriminant and a is cofficient of y^2
a = 1 and D = b^2 - 4ac = 16 - 44 = -28
So minimum value -D/4a = 28/4 = 7
Now ...Lim x-->0 [ 7sinx/x ]
Sinx/x is always less than 1....and is always positive.... for case of x---> 0
If you will draw the graph of sinx and x superimposed on each other....then for x>0 line x is above the sinx....so ration of sinx/x is always less than 1 and positive ..
and in similar fashion for x<0 x i below the sinx ..but
it simply means at every point ...x is something like -5 and sinx as something like -0.5 ...
so again when you take ratio ...sinx/x will be positive coz negative sign will be canceled out..and ratio will come out to be less than 1.
So 6 < 7 sinx/x < 7 for case ...x-->0+ or 0-
so [ 7sinx/x] = 6 answere
Did u get it or not...
let me know it
With regards
Yagya
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