 ×     #### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
When 242 is divided by a certain divisor the remainder obtained is 8. When 698 is divided by the same divisor the remainder obtained is 9. However, when the sum of the two numbers 242 and 698 is divided by the divisor, the remainder obtained is 4. What is the value of the divisor?

```
11 years ago

```							Let the divisor be d.

When 242 is divided by the  divisor, let the quotient be 'x' and we know that the remainder is  8.
Therefore, 242 = xd + 8

Similarly, let y be the quotient when 698  is divided by d.
Then, 698 = yd + 9.

242 + 698 = 940 = xd + yd + 8 +  9
940 = xd + yd + 17
As xd and yd are divisible by d, the remainder when  940 is divided by d should have been 17.

However, as the question states  that the remainder is 4, it would be possible only when Remainders, division  leaves a remainder of 4.

If the remainder obtained is 4 when 17 is  divided by d, then d has to be 13.
```
11 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Magical Mathematics[Interesting Approach]

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions