(1)HOW many ways 4 letter can be selected fromthe word examination .
Manish kumar , 5 Years ago
Grade 12th pass
Magical Mathematics[Interesting Approach]> (1)HOW many ways 4 letter can be selected...
1 Answers
Arun
Last Activity: 5 Years ago
We have, 11 letters: {A, A, E, I, I, O, M, N, N, T, X};
Out of them there are 3 pairs: {A, A}, {I, I} and {N, N}.
So, # of distinct letters is 8: {A, E, I, I, O, M, N, N, T, X}
As pointed out, there are 3 different cases possible.
Out of them there are 3 pairs: {A, A}, {I, I} and {N, N}.
So, # of distinct letters is 8: {A, E, I, I, O, M, N, N, T, X}
As pointed out, there are 3 different cases possible.
{abcd} all 4 letters are distinct:
8C4 = 70
{aabc} - two letters are alike and other two are distinct:
3C1 * 7C2 = 63
{aabb} - two letters are alike and other two letters are also alike:
3C2 = 3
Total=70+63+3=136.
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