1/a,1/b,1/c are in ap .Show that (b+c)/a,(c+a)/b,(a+b)/c

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Vikas TU · Answer

The question is not complete.Considereing the question to be 1/a,1/b,1/c are in ap .Show that (b+c)/a,(c+a)/b,(a+b)/c are in AP. Given that 1/a,1/b,1/c are in AP Increase each term by (a+b+c).The result will likewise be in AP. (a+b+c)/a , (a+b+c)/b , (a+b+c)/c are in AP Subtracting 1 from each term will likewise be in AP (a+b+c)/a - 1 , (a+b+c)/b - 1, (a+b+c)/c-1 Consequently (b+c)/a,(c+a)/b,(a+b)/c are in AP

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1/a,1/b,1/c are in ap .Show that (b+c)/a,(c+a)/b,(a+b)/c

1/a,1/b,1/c are in ap .Show that (b+c)/a,(c+a)/b,(a+b)/c

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