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Find the sum of 13/1+ (13+23/1+3) +(13+23+33/1+3+5) + ….......16 terms.
Options: 442,446,448,447

Neetu , 7 Years ago
Grade 12
anser 1 Answers
Arun

Last Activity: 7 Years ago

Dear Neetu
For nth term
Tn = (1³ + 2³ +3³+..,..+n³)/(1 +3+5+....(2n-1))
Tn = n²(n+1)²/[4 *(n/2)(2n)]
Tn = (n+1)²/4
Tn = (n² + 1 + 2n) /4
Now 
Sn = sigma Tn
Then put n = 16 in Sn
Now you can solve 
Regards
Arun (askIITians forum expert)

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