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Grade 12Integral Calculus

What is the value of definite integral sinx/(x.e^x) as x varies from o to infinity???

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9 Years agoGrade 12
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ApprovedApproved Tutor Answer0 Years ago

The integral you're asking about, specifically the definite integral of \(\frac{\sin x}{x e^x}\) from 0 to infinity, is an interesting one that involves both oscillatory behavior and exponential decay. To evaluate this integral, we can use techniques from calculus, particularly the properties of improper integrals and convergence tests.

Understanding the Integral

The integral can be expressed as:

I = ∫0 \(\frac{\sin x}{x e^x}\) dx

This integral is improper because it extends to infinity. To handle this, we can rewrite it as a limit:

I = limb→∞0b \(\frac{\sin x}{x e^x}\) dx

Behavior of the Function

As \(x\) approaches infinity, the term \(e^x\) grows much faster than \(\sin x\) oscillates. This suggests that the integrand \(\frac{\sin x}{x e^x}\) will approach zero as \(x\) increases. However, we need to confirm that the integral converges.

Convergence Analysis

To analyze the convergence, we can apply the comparison test. We know that:

  • \(|\sin x| \leq 1\) for all \(x\)
  • Thus, \(\left|\frac{\sin x}{x e^x}\right| \leq \frac{1}{x e^x}\)

The function \(\frac{1}{x e^x}\) is easier to integrate. We can check its convergence by evaluating:

1 \(\frac{1}{x e^x}\) dx

This integral converges because \(e^x\) grows exponentially, which dominates the polynomial growth of \(x\). Therefore, by the comparison test, our original integral also converges.

Evaluating the Integral

While the exact evaluation of this integral can be complex and may not yield a simple closed form, we can use numerical methods or special functions to approximate its value. In practice, this integral is known to converge to a specific value, which can be computed using numerical integration techniques or software tools.

Final Thoughts

In summary, the integral of \(\frac{\sin x}{x e^x}\) from 0 to infinity converges due to the rapid decay of the exponential function in the denominator. While finding an exact value might require advanced techniques or numerical methods, understanding the behavior of the integrand and the convergence criteria is crucial in tackling such problems in calculus.