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What is the minimum value of f(x) = 03e|x-t|dt where x ∈ [0,2] ? (0 is the lower limit and 3 is the upper limit)

Shibashis Mallik , 11 Years ago
Grade 12
anser 2 Answers
Neha
e*3+2*e^2+2e-5
Last Activity: 11 Years ago
Shibashis Mallik
please explain..
Last Activity: 11 Years ago
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