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Grade 12Integral Calculus

What is the minimum value of f(x) = 03e|x-t|dt where x ∈ [0,2] ? (0 is the lower limit and 3 is the upper limit)

Profile image of Shibashis Mallik
11 Years agoGrade 12
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2 Answers

Profile image of Neha
11 Years ago
e*3+2*e^2+2e-5
Profile image of Shibashis Mallik
11 Years ago
please explain..