Guest

What is the minimum value of f(x) = 0 ∫ 3 e |x-t| dt where x ∈ [0,2] ? (0 is the lower limit and 3 is the upper limit)

What is the minimum value of f(x) = 03e|x-t|dt where x ∈ [0,2] ? (0 is the lower limit and 3 is the upper limit)

Grade:12

2 Answers

Neha
10 Points
7 years ago
e*3+2*e^2+2e-5
Shibashis Mallik
21 Points
7 years ago
please explain..

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free