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what is the intrigation value of tanx/(tan(x)^2+tan(x)+1)

chandan banerjee , 7 Years ago
Grade 12
anser 1 Answers
Arun

Last Activity: 7 Years ago

Dear Chandan
multiply by tan x in numerator and denominator
tan2x / [(tan x) * (tan2 x + tan x +1)]
= sec2 x – 1 / [(tan x) * (tan2 x + tan x +1)]
now put tanx = t
sec2 x * dx = dt
now, it becomes
[dt / t (t2 + t +1) ]– dx/ tanx (tan2 x +tan x +1)
now you can solve it
Regards
Arun (askIITians forum expert)

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