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Grade: 12
        what is the intrigation value of tanx/(tan(x)^2+tan(x)+1)
8 months ago

Answers : (1)

Arun
13797 Points
							
Dear Chandan
multiply by tan x in numerator and denominator
tan2x / [(tan x) * (tan2 x + tan x +1)]
= sec2 x – 1 / [(tan x) * (tan2 x + tan x +1)]
now put tanx = t
sec2 x * dx = dt
now, it becomes
[dt / t (t2 + t +1) ]– dx/ tanx (tan2 x +tan x +1)
now you can solve it
Regards
Arun (askIITians forum expert)
8 months ago
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