Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
what is the integration of (sin -1 x) 2? what is the integration of (sin-1x)2?
?(sin-1x)2dx put sin-1x=t => x=sint dx=cost dt ?t2costdt =t2sint-?2t.sintdt =t2sint-2[-tcost+?costdt] =t2sint+2tcost-2sint +C =(sin-1x)2x+2sin-1xv(1-x2)-2x+ C Thanks & Regards Rinkoo Gupta AskIITians Faculty
?(sin-1x)2dx
put sin-1x=t => x=sint
dx=cost dt
?t2costdt
=t2sint-?2t.sintdt
=t2sint-2[-tcost+?costdt]
=t2sint+2tcost-2sint +C
=(sin-1x)2x+2sin-1xv(1-x2)-2x+ C
Thanks & Regards
Rinkoo Gupta
AskIITians Faculty
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -