# What is the integration of: logx/((1+logx)^2 ) ? (Type: Class 12th, Indefinite Integrals)

Sourabh Singh IIT Patna
Setting log x = t, we can rewrite the integral as $\int \frac{e^tt}{(1+t)^2} \ dt = \int e^t \left(\frac{1}{1+t} - \frac{1}{(1+t)^2)} \right ) \ dt$