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What is the integration of: ax+b (ax^2+b)^1/2 dx ? The answer is 1/3(ax^2 + b)^3/2 + (b/2)x (ax^2+b)^1/2 + b^2/2a^1/2 log a^1/2 x + (ax^2 + b)^1/2 + c

What is the integration of:
ax+b (ax^2+b)^1/2 dx ?
 
 
The answer is 1/3(ax^2  + b)^3/2 + (b/2)x (ax^2+b)^1/2 + b^2/2a^1/2 log a^1/2  x + (ax^2  + b)^1/2 + c
 
 

Grade:12th pass

1 Answers

Arun
25758 Points
3 years ago
Dear student
 
its Integration can be achieved by formula directly.
 
1/3(ax^2  + b)^3/2 + (b/2)x (ax^2+b)^1/2 + b^2/2a^1/2 log a^1/2  x + (ax^2  + b)^1/2

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