# what is the integration of?1. (x2 +1)/x4+1 2.(sin-1x)2

Arun Kumar IIT Delhi
8 years ago
Hi
I'll give only one answer for second question make another post.

$\\\int \frac{\left(x^2+1\right)}{x^4+1}dx\:=\:\frac{tan^{-1} \left(\sqrt{2}x+1\right)-tan^{-1} \left(1-\sqrt{2}x\right)}{\sqrt{2}}+C$
Seeing the arguments in the tan inverse you can figure out how to break the expression.

Thanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty

Mostafijur Rahaman
40 Points
8 years ago
please give me the clue to break it.