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`        What is the Integration of 1/[(cos(x-a)cos(x-b)] dx`
3 years ago

```							In these questions..  Remember a rule to multiply and divide by sin(a-b)  if both the trigonometric function is same ie sin n sin or cos n cos...  If they are different then multiply and divide by cos(a-b)...  And apply trigonometric formulae to get ur integration
```
3 years ago
```							∫{1/[(cos(x-a)cos(x-b)] } dx(1/sin(a-b)}∫{sin[(x-a)-(x-b)]}/[(cos(x-a)cos(x-b)]} dx(1/sin(a-b)}∫{sin(x-a)*cos(x-b)-sin(x-b)*cos(x-a)}/[(cos(x-a)cos(x-b)]dx(1/sin(a-b)}∫{sin(x-a)/(cos(x-a)-sin(x-b)/cos(x-b)}dx(1/sin(a-b)}∫{tan(x-a)-tan(x-b)}dx(1/sin(a-b)}[-ln |cos (x-a)| + -ln |cos (x-b)| ]+ C
```
3 years ago
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