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What is integration of function x^x.................???
DEAR ABHISHEK let J = ∫ x^x dx take natural logs on both sidesln(J) = ln ∫ x^x dx = ∫ ln(x^x) dx = ∫ xln(x) dx using integration by partsln (J) = [((x^2)/2)ln(x)] - ∫ ((x^2)/2)(1/x) dx = [((x^2)/2)ln(x)] - ∫ (x/2) dx ln (J) = ln[(x^2)/exp]^[(x^2)/4] take exponentials on both sidesJ = [(x^2)/exp]^[(x^2)/4] + Arbitrary ConstantHOPE IT CLEARS NOW REGARDS
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