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Grade: 12th pass
        What is indefinite Integration of (1+tanx)^(squareroot)
one year ago

Answers : (2)

Nishant Vora
IIT Patna
askIITians Faculty
2468 Points
							Take 1 + tanx = t
hence sec^2 x dx = dt
sec^2x = 1 + (t-1)^2

so dx = dt /1 + (t-1)^2

So

Integration of (1+tanx)^(squareroot) = root(t) dt /1 + (t-1)^2
Now proceed

Thanks
one year ago
kamalesh bagrecha
21 Points
							That much i have already done...Tell me after that how ti procede                 And how could i know that which function is integrable
						
one year ago
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