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Multiply and divide by 2.
I= dx/root(3) sinx+cosx then 2I= dx/(root(3)/2 *sinx + (cosx)/2 )
then root(3)/2=cos30 1/2 = sin 30
then root(3)sinx+ cosx becomes 2sin(30+x) . then the integration becomes integration of cosec(x+30) multiplied by 1/2. which equals [log(tan(x+30)/2))] . 1/2+constant.
Regards
Arun (askIITians forum expert)
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