The value of ∫1/sin(x-a)cos(x-b)dx is equal to=====

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Romita · Answer

Since the given functions in denominator are 2 different functions , divide and multiply numirator and deno. By cos(b-a) then it will yeild tan (x-a)and tan(x-b) seperately . Which can be simply integrated .. .

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The value of ∫1/sin(x-a)cos(x-b)dx is equal to=====

The value of ∫1/sin(x-a)cos(x-b)dx is equal to=====

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The value of ∫1/sin(x-a)cos(x-b)dx is equal to=====

The value of ∫1/sin(x-a)cos(x-b)dx is equal to=====

1 Answers

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