The fourth term of an A.P is equal to 3 times the first term. Its 9th term is 38. Find the 15th term.

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Arun · Answer

Dear student T4 = 3T1 = 3a T9 = 38 = a + 8d Also a + 3d = 3a 3d = 2a Now Solve the equations 76 = 2a + 16d 76 = 19d d = 4 Hence a = 6 Now 15th term (T15) = a + 14 d = 6 + 56 = 62 Regards Arun(askIITians forum expert)

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The fourth term of an A.P is equal to 3 times the first term. Its 9th term is 38. Find the 15th term.

The fourth term of an A.P is equal to 3 times the first term. Its 9th term is 38. Find the 15th term.

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The fourth term of an A.P is equal to 3 times the first term. Its 9th term is 38. Find the 15th term.

The fourth term of an A.P is equal to 3 times the first term. Its 9th term is 38. Find the 15th term.

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Other Related Questions on Integral Calculus

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