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The even and odd functions can be applied only when the integral is a definite one. (I.e)
Only when the limit is -a to +a. Then we cannot say that ∫|x| is an even function ..right?then how to integrate an indefinite integral ∫| x| and ∫| x-4| ??

Sreevignesh , 8 Years ago
Grade 12
anser 1 Answers
Askiitians Tutor Team

Last Activity: 5 Months ago

When we talk about even and odd functions, we often refer to their properties in relation to definite integrals, particularly over symmetric intervals like from -a to +a. However, this doesn't mean we can't work with these functions in the context of indefinite integrals. Let's break this down step by step.

Understanding Even and Odd Functions

First, let's clarify what even and odd functions are:

  • Even functions: A function f(x) is considered even if f(-x) = f(x) for all x in its domain. Graphically, even functions are symmetric about the y-axis.
  • Odd functions: A function f(x) is odd if f(-x) = -f(x) for all x in its domain. These functions have rotational symmetry about the origin.

Definite Integrals and Symmetry

When you evaluate a definite integral of an even function over a symmetric interval, you can simplify the calculation. For example, if you have an even function f(x), then:

∫ from -a to a of f(x) dx = 2 * ∫ from 0 to a of f(x) dx.

For odd functions, the integral over a symmetric interval is zero:

∫ from -a to a of f(x) dx = 0.

Indefinite Integrals of Absolute Functions

Now, let's focus on your question about the indefinite integrals of |x| and |x - 4|. The absolute value function can be tricky because it behaves differently depending on the input value.

Integrating |x|

The function |x| can be expressed piecewise:

  • For x ≥ 0, |x| = x
  • For x < 0, |x| = -x

To find the indefinite integral of |x|, we can break it into two cases:

∫|x| dx = ∫x dx (for x ≥ 0) = (1/2)x² + C

∫|x| dx = ∫-x dx (for x < 0) = -(1/2)x² + C

Thus, the complete indefinite integral can be expressed as:

∫|x| dx = (1/2)x² + C, for x ≥ 0

∫|x| dx = -(1/2)x² + C, for x < 0

Integrating |x - 4|

Similarly, for |x - 4|, we need to determine where the expression changes:

  • For x < 4, |x - 4| = -(x - 4) = 4 - x
  • For x ≥ 4, |x - 4| = x - 4

Thus, the indefinite integral can be computed as follows:

For x < 4:

∫|x - 4| dx = ∫(4 - x) dx = 4x - (1/2)x² + C

For x ≥ 4:

∫|x - 4| dx = ∫(x - 4) dx = (1/2)x² - 4x + C

Final Thoughts

In summary, while the properties of even and odd functions are particularly useful for definite integrals over symmetric intervals, they do not limit our ability to integrate functions like |x| and |x - 4| in the indefinite sense. By breaking these functions into their respective cases, we can effectively compute their integrals. This approach not only clarifies the integration process but also enhances our understanding of how absolute values behave across different intervals.

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