The area enclosed by the curve y 2 + x 4 = x 2 is- (a)2/3 (b)4/3 (c)8/3 (d)10/3

Question

Arun · Answer

Dear student

This curve is symmetrical along the x and y axis, so we can integrate the area in the first quadrant and multiply it by 4.

y = x(√(1-x^2))

A = ∫ 0->1 x(√(1-x^2)) dx

A = -1/3 (1-x^2)^(3/2) | 0->1

A = 1/3

Total Area is 1/3 x 4 = 4/3

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The area enclosed by the curve y 2 + x 4 = x 2 is- (a)2/3 (b)4/3 (c)8/3 (d)10/3

The area enclosed by the curve y² + x⁴ = x² is-
(a)2/3
(b)4/3
(c)8/3
(d)10/3

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The area enclosed by the curve y 2 + x 4 = x 2 is- (a)2/3 (b)4/3 (c)8/3 (d)10/3

The area enclosed by the curve y2 + x4 = x2 is-(a)2/3(b)4/3(c)8/3(d)10/3

1 Answers

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The area enclosed by the curve y² + x⁴ = x² is-
(a)2/3
(b)4/3
(c)8/3
(d)10/3