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The area enclosed by the curve y2 + x4 = x2 is-(a)2/3(b)4/3(c)8/3(d)10/3
Dear student This curve is symmetrical along the x and y axis, so we can integrate the area in the first quadrant and multiply it by 4. y = x(√(1-x^2)) A = ∫ 0->1 x(√(1-x^2)) dx A = -1/3 (1-x^2)^(3/2) | 0->1 A = 1/3 Total Area is 1/3 x 4 = 4/3
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